A fringe width of a certain interference pattern is `beta=0.002` cm What is the distance of 5th dark fringe centre?

A fringe width of a certain interference pattern is beta=0.002 cm. What is the distance of 5^(th) dark fringe from centre ?

Fringe width equal to 1 mm is observed in the interference pattern of biprism experiment. Then the distance of nearest bright fringe from the central bright fringe will be :

In Y.D.S.E., slits are at a distance of 0.5 mm and light of wavelength lambda is used. Determine the value of lambda if interference pattern is formed at a distance 1.2 m away and third dark fringe is at a distance of 1.2 cm from the central fringe.

How does the width of dark fringe in interference pattern vary from that of the bright fringe ?

In Y.D.S.E., light of wavelength 5500 Å is used. If the slits are at a distance of 10^(-3) m and interference pattern is formed at a distance of 100 cm. Calculate the distance between central fringe and second dark fringe.

The width of an interference fringe is 1.5 mm . What would be the width of the fringe if the separation between the slits is made twice the original value?

In Y.D.S.E., slits are at a distance of 0.5 mm and light of wavelength λ is used, if interference pattern is formed at a distance 1.2 m away and third dark fringe is at a distance of 1.2 cm from the central fringe, calculate the distance between central fringe and third dark frings if whole set-up is immersed in a liquid of refractive index 1.33.

Define coherent sources of light, fringe width and interference of light. Show that the width of dark fringe is equal to the width of bright fringe in Young's double slit experiment.