If a body is executing simple harmonic motion and its current displacement is `sqrt(3)//2` times the amplitude from its mean position , then the ratio between potential energy and kinetic energy is

A body is executing simple harmonic motion. At a displacement x (from its mean position) its potential energy is E_(1) and at a displacement y its potential energy is E_(2) . The potential energy is E at displacement (x+y) . Then:

A body is executing simple harmonic motion. At a displacement x (from its mean position) its potential energy is E_(1) and at a displacement y its potential energy is E_(2) . The potential energy is E at displacement (x+y) . Then:

Amplitude of a SHO is sqrt(5) cm . At what displacement from the mean position the ratio of kinetic energy to potential energy is 4?

Assertion: In a simple harmonic motion the kinetic and potential energy becomes equal when the displacement is (1)/(sqrt(2)) time the amplitude Reason: is SHM kinetic energy is zero when potential energy is maximum

A body is executing simple harmonic motion. At a displacement x, its potential energy is E_1 and a displacement y, its potential energy is E_2 . The potential energy E at a displacement (x+y) is

A body is executing simple harmonic motion. At a displacement x, its potential energy is E_1 and a displacement y, its potential energy is E_2 . The potential energy E at a displacement (x+y) is

A body is executing simple harmonic motion. At a displacement x, its potential energy is E_1 and a displacement y, its potential energy is E_2 . The potential energy E at a displacement (x+y) is

A body is executing simple harmonic motion As x displacement x its potential energy is E_(1) and at a displacement y its potential energy is E_(2) The potential energy E at displacement (x+y) is

The total meachanical energy of a particle executing simple harmonic motion is E when the displacement is half the amplitude is kinetic energy will be

A body is executing simple harmonic motion. At a displacement x from mean position, its potential energy is E_(1)=2J and at a displacement y from mean position, its potential energy is E_(2)=8J . The potential energy E at a displacement (x+y) from mean position is