`^^_(m)^(@)` for `NaCI,HCI` and `NaA` are `126.4,425.9` and `100.5Scm^2 m ol^(-1)`, respectively. If the conductivity of `0.001 MHA` is `5xx10^(-5)Scm^(-1)`, degree of dissociation of HA is :

lamda_m^0 for NaCl,HCL and NaAc are 126.4,425.9and 91.0Scm^2mol^(-1) respectively. Calculate ^^_m^0 for Hac.

Lambda_(m)^(@) for NaCl, HCl and NaAc are 126.4, 425.9 and "91 S.cm"^(2)."mol"^(-1) respectively. Calculate Lambda^(@) for Hac.

overset(@)wedge for NaCI HCI and NaAC are 126.4 425.9 , and 91.0 S cm^(2) "mol"^(-1) respectively calulate overset(infty)wedge m for Hac.

Calculate molar conductivity of CH_(3)COOH at infinit e dilution if A_(m)^(@) for NACI,HCI and CH_(3)COONA are 126.45,426.16 an 91 S cm(^2) mol^(-1) respectively The molar conductivity of CH 3 ​ COOH at infinite dilution is 390.71 Scm (^)2 mol −1 .

Lambda_(m)^(@) of NaCl, HCl and CH_(3)COONa are 126.4, 425.9 and "91.0 S.cm"^(2)."mol"^(-1) respectively. Lambda_(m)^(@) for CH_(3)COOH will be -

At 298 K molar conductivities at infinite dilution ( wedge_(m)^@) of NH_(4)Cl , KOH and KCl are 152.8, 272.6 and 149.8 S cm^(2)mol^(-1) respectively. The wedge_(m)^@ of NH_(4)OH in Scm^(2) mol^(-1) and % dissociation of 0.01 M NH_(4)OH with wedge_(m) =25.1 Scm^(2) mol^(-1) at the same temperature are,

A monoprotic acid in 0.1 M solution has K_(a)=1.0xx10^(-5) . The degree of dissociation for acid is

The limiting molar conductivities ^^ ^@ for NaCl , KBr and KCl are 126, 152 and 150 Scm^2 mol^(-1) respectively. The for NaBr is

At 25^@ C, the ionic mobility of CH_3COO^(-), H^+ are respectively 4.1 xx 10^(-4), 3.63 xx 10^(-3) cm/sec. The conductivity of 0.001M CH_3COOH is 5xx10^(-5)S.cm^(-1) . Dissociation constant of CH_3 COOH is