Find the angle of intersection of the circles `x^2+y^2-6x+4y+11=0andx^2+y^2-4x+6y+9=0`

The equation of the circle having its centre on the line x+2y-3=0 and passing through the points of intersection of the circles x^(2)+y^(2)-2x-4y+1=0andx^(2)+y^(2)-4x-2y+4=0 is x^(2)+y^(2)-6x+7=0x^(2)+y^(2)-3y+4=0 c.x^(2)+y^(2)-2x-2y+1=0x^(2)+y^(2)+2x-4y+4=0

The equation of the circle having the center on the line x+2y-3=0 and passing through the point intersection of the circles x^(2)+y^(2)-2x-4y+1=0andx^(2)+y^(2)-4x-2y+4=0 is x^(2)+y^(2)-6x+7=0x^(2)+y^(2)-3u-2y+4=0x^(2)+y^(2)-2x-2y+1=0x^(2)+y^(2)+2x-2y+4=0

Find the angle between the circles S:x^(2)+y^(2)-4x+6y+11=0andS':x^(2)+y^(2)-2x+8y+13=0

Find the angle between the circles S:x^(2)+y^(2)-4x+6y+11=0andS':x^(2)+y^(2)-2x+8y+13=0

Find the angle between the circles S:x^(2)+y^(2)-4x+6y+11=0andS':x^(2)+y^(2)-2x+8y+13=0

Find the angle between the circles S:x^(2)+y^(2)-4x+6y+11=0andS':x^(2)+y^(2)-2x+8y+13=0

The angle between the circles x^2+y^2-2x-4y+3=0 and x^2+y^2-4x-6y+11=0 is

The angle between the circles x^2+y^2-2x-4y+3=0 and x^2+y^2-4x-6y+11=0 is

Find the equation of the circle through the points of interrection of the circles x^(2)+y^(2)-4x-6y-12=0 and x^(2)+y^(2)+6x+4y-12=0 and cutting the circle x^(2)+y^(2)-2x-4=0 orthogonally.