If `A=[(cos theta, sin theta),(-sin theta, cos theta)]`

The inverse of A=[( cos theta, sin theta),(-sin theta, cos theta)] is

Find A^(-1) using adjoint method, where A = [(cos theta,sin theta),(-sin theta,cos theta)]

Verify that [(cos theta, sin theta),(-sin theta, cos theta)] and [(cos theta, - sin theta),(sin theta, cos theta)] are inverse of each other.

The multiplicative inverse of A = [(cos theta,-sin theta),(sin theta,cos theta)]is

Let A=[(cos theta, -sin theta),(- sin theta,-cos theta)] then the inverse of a is

Let theta = (pi)/(5) and A =[{:(cos theta, sin theta),(-sin theta, cos theta):}] . If B = A + A^(4) , then det (B).

The multiplicative inverse of : A = [(cos theta , -sin theta ),(sin theta , cos theta )] is :