Home
Class 11
MATHS
Let n=180. Find the number of positive i...

Let `n=180`. Find the number of positive integral divisors of `n^2`, which do not divide n

Text Solution

Verified by Experts

n=180=20*4
n=`2^2*3^2*5`
`D_1=(2+1)(2+1)(1+1)-1`
`D_1=17-(1)`
`n^2=2^4*3^4*5^2`
`D_2=(4+1)(4+1)(3)-2`
`D_2=73-(2)`
subtracting equation 1 from 2
...
Promotional Banner

Similar Questions

Explore conceptually related problems

The number of positive integral solutions of x+y+z=n,n in N,n>=3 is

The number of positive integral solutions of x+y+z=n,n in N, n >= 3 is

Find the number of positive integers n such that 105 is a divisor of n^2+n+1.

Find the number of positive integers n such that 105 is a divisor of n^(2)+n+1

For a positive integer n, define d(n) - the number of positive divisors of n. What is the value of d(d(d(12))) ?