(tan70-tan20-2tan40)/(tan10)=?

The value of (tan70^@-tan20^@)/(tan50^@)=

The value of (tan70^(0)-tan20^(0))/(tan50^(0)) =

Prove that tan70^(@)-tan20^(@)-2tan40^(@)=4tan10^(@) . (b) In a DeltaABC , if a=2sqrt3,b=2sqrt2andC=75^(@) find the other side and the angles.

The value of (tan70^(@)-tan20^(@))/(tan50^(@))=

tan20^(@)tan40^(@)tan80^(@)

Prove that tan 70^(@)-tan 20^(@)-2 tan 40^(@)=4 tan 10^(@)

The value of (tan 70^(@) -tan 20^(@))/(tan 50^(@)) is-

Find the value of : ((3tan41^@)/(cot49^@))^2-((sin35^@ sec55^@)/(tan10^@ tan20^@ tan60^@ tan70^@ tan80^@))^2

Without using Trigonometric Tables evaluate the following :- (sin^2 35^@+sin^2 55^@)/(tan10^@tan20^@tan30^@tan70^@tan80^@) .