`2costheta-cos 3 theta-cos5 theta-16cos^3 theta sin^2 theta=`

2cos theta-cos3 theta-cos5 theta-16cos^(3)theta sin^(2)theta=

2 cos theta - cos 3 theta - cos 5 theta - 16 cos^(3) theta sin^(2) theta =

cos theta-cos3 theta+cos5 theta-cos7 theta=4sin theta sin4 theta cos2 theta

(cos3 theta+2cos5 theta+cos7 theta)/(cos theta+2cos3 theta+cos5 theta)=cos2 theta-sin2 theta tan3 theta

The value of (2(sin2 theta+2cos^(2)theta-1))/(cos theta-sin theta-cos3 theta+sin3 theta)=

Prove that (cos3 theta+2cos5 theta+cos7 theta)/(cos theta+2cos3 theta+cos5 theta)=cos2 theta-sin2 theta tan3 theta

The value of (2 (sin2 theta-2 cos^(2)theta-1))/(cos theta-sin theta-cos 3 theta +sin 3 theta)=

64cos^(3)theta sin^(4)theta=cos7 theta-cos5 theta-3cos3 theta+3cos theta

64cos^(3)theta sin^(4)theta=cos7 theta-cos5 theta-3cos3 theta+3cos theta

The value of (sin^3 theta + cos^3 theta)/(sin theta+ costheta)+((cos^3 theta - sin^3 theta))/(cos theta - sin theta) is