A charged ball of mass `8.4xx10^(16) kg` is found to remain suspended in a uniform electric field of `2xx10^(4) Vm^(-1)`. Calculate the charge on the ball. Given `g = 10 m//s^(2)`

A charged oil drop weighing 1.6 xx 10^(-15) N is found to remain suspended in a uniform electric field of intensity 2 xx 10^3NC^(-1) . Find the charge on the drop.

A charged particle of mass 3 xx 10^(-6) kg is held stationary in spacing in an electric field of strength 10^(6) NC^(-1) directed vertically downwards. The charge on the particle is ( g = 10 ms^(-2))

An alpha particle of mass 6.4xx10^(-27) kg and charge 3.2xx10^(-19)C is situated in a uniform electric field of 1.6xx10^(5)Vm^(-1) . The velocity of the particle at the ennd of 2xx10^(-2)m path when it starts from rest is

A particle of mass 6.4xx10^(-27) kg and charge 3.2xx10^(-19)C is situated in a uniform electric field of 1.6xx10^5 Vm^(-1) . The velocity of the particle at the end of 2xx10^(-2) m path when it starts from rest is :

A charged oil drop is suspended in uniform field of 3 xx 10^(4) Vm^(-1) so that it neither falls nor rises. The charge on the drop will be

A charged oil drop is suspended in uniform field of 3 xx 10^(4) Vm^(-1) so that it neither falls nor rises. The charge on the drop will be ...(mass of the charge = 9.9xx 10^(-15) kg

In Millikan's oil drop experiment, an oil drop mass 60 xx 10^(-6) kg is balanced by an electric field of 10^(6) V//m . The charge in coulomb on the drop, assuming g = 10 m//s^(2) is

In the figure shown a ball is suspended from the ceiling of a room in a uniform electric field of magnitude 2xx10^(4) V/m . If the mass of the ball is 25 g and the charge on the ball is 3muC . The angle theta is (g=9.8ms^(-2))