If `f(x)` is differentiable then `f'(x)=`

f:R rarr R,f(x) is differentiable such that f(x)=k(x^(5)+x).(kne0) Then f(x) is

If f(x) is differentiable function and f(x)=x^(2)+int_(0)^(x) e^(-t) (x-t)dt ,then f)-t) equals to

f:RtoR ,f(x) is differentiable such that f(f(x))=k(x^(5)+x),(kne0) . Then f(x) is always

f:R rarr R,f(x) is differentiable such that f(x)=k(x^(5)+x).(kne0) Then f(x) is increasing . In the above question k can take value,

f:R rarr R,f(x) is differentiable such that f(f(x))=k(x^(5)+x),k!=0). Then f(x) is always increasing (b) decreasing either increasing or decreasing non-monotonic

f: RvecR ,f(x) is differentiable such that f(f(x))=k(x^5+x),k!=0)dot Then f(x) is always increasing (b) decreasing either increasing or decreasing non-monotonic

f: RvecR ,f(x) is differentiable such that f(f(x))=k(x^5+x),k!=0)dot Then f(x) is always increasing (b) decreasing either increasing or decreasing non-monotonic

f: R to R ,f(x) is differentiable such that f(f(x))=k(x^5+x),k!=0)dot Then f(x) is a) always increasing (b) decreasing either increasing or decreasing c) non-monotonic

If f (x) is odd and differentiable , then f'(x) is

Assertion : f(x) = floor(x) is not differentiable. Reason f(x) = floor(x) is not continuous at x = 0