if `ay^4=(x+b)^5` then `5yy_2=`

If ay ^(4) = (x+ b) ^(5) then 5 y y_(2)=

If ay^(4)=(x+b)^(5) then show that 5yy''=(y')^(2).

If x^2+y^2=1 , then a. y y''-2(y^(prime))^2+1=0 b. yy''+(y^(prime))^2+1=0 c. yy''+(y^(prime))^(-2)-1=0 d. yy''+2(y^(prime))^2+1=0

If x^(2)+y^(2)=1 , then a) yy''+(y')^(2)+1=0 b) yy''+2(y')^(2)+1=0 c) yy''-2(y')^(2)+1=0 d) yy''+(y')^(2)-1=0

The value of (x^a.y^(-b))^5(x^5.y^2) is

If ax+by=6, bx-ay=2and x^(2)+y^(2)=4 then what is (a^(2)+b^(2)) ?

If ((x-2y,5y),(6,a-2b))=5((4,2),((b)/(5),6)) then a+x=

If x/a+y/b=1 " intersects " 5x^2+5y^2+5bx+5ay-9ab=0 at P and Q, anglePOQ=pi//2 then the relation between a and b is

The equation of the line passing through the point (x', y') and perpendicular to the line y y'=2a (x+x') is ................ A) x y'+2ay+ 2 ay' -x'y'=0 B) x y' +2ay-2ay' -x'y'=0 C) x y' +2ay+2ay' -x'y'=0 D) xy'+ 2ay-2ay' +x'y'=0