A soap film measure `10cmxx6cm`. It is increased to `10cmxx12cm`. IF surface tension is `30xx10^-3` newtor per metre. Then the work done is

The dimensions of a soap film is 10 cm xx 6 cm. If it is increased to 10 cm xx 11 cm, then work done is 3xx10^-4 J. What is the surface tension of the soap solution?

The radius of a soap bubble is increased from (1)/(sqrtpi) cm to (2)/(sqrtpi) cm. If the surface tension of water is 30dynes per cm, then the work done will be

Assertion : if work done in increasing th size of a soap film from 10 cm xx 4 cm to 10cm xx8cm is 2xx10^(-4) J, then the surface tension is 5xx10^(-4)N m^(-1) Reason : work done = surface tension xx increase in area .

Assertion : if work done in increasing th size of a soap film from 10 cm xx 4 cm to 10cm xx8cm is 2xx10^(-4) J, then the surface tension is 5xx10^(-4)N m^(-1) Reason : work done = surface tension xx increase in area .

A soap film in on a rectangular wire of size 4 cm xx 4 cm. If the size of the film is changed to 5 cm xx 5 cm, then calculate the work done in this process. The surface tension of soap film is 6xx10^(-2) Nm^(-1)

The work done which is to be required to increase the area of soap film of 10cmxx6cm to 10cmxx11cm is 3xx10^(-4) J. The surface tension of the soap film is

A rectangular film of liquid is extended from 5 cm xx 3 cm to 6 cm xx 5 cm . If the work done is 3.0 xx 10^(-4) J . The surface tension of liquid is

The amount of work done in forming a soap film of size 10 cm x 10 cm is (Surface tension T=3xx10^(-2) N//m )