[" In a triangle "ABC," if "a=6,b=3" and "cos(A-B)=(4)/(5)],[" then "Delta=]

In a triangle ABC, two sides are a = 6, b = 3 and cos(A-B) =(4)/(5) then the area of the triangle is

In Delta ABC, if a = 6, b=3 and cos (A-B) = (4)/(5) " then " angle C =

If in a triangle ABC,a=6,b=3 and cos(A-B)=(4)/(5) find the area of the triangle.

(i) If a:b:c= 2:3:4 and s=27 inches, find the area of the triangle ABC. (ii) If in a triangle ABC, a=6, b=3 and cos(A-B) =4/5 then find its area.

If in a triangle ABC , a = 6 , b = 3 and cos (A -B) = 4/5 ,then its area in square units, is

If in Delta ABC,a=5,b=4 and cos(A-B)=(31)/(32) ,then

In triangle ABC, a=5, b=4 and cos(A-B)=(31)/(32) In this triangle, c=