A particle moving in a straight in a straight line has velocity and displacement equation as
`v = 4 sqrt(1 + s)`,
where `v` is in m/s and s is in m. The initial velocity of the particle is:

A particle moving in a straight line has velocity-displacement equation as v = 5 sqrt(1 + s). Here v is in ms^-1 and s in metres. Select the correct alternative.

A particle moving in a straight line has velocity-displacement equation as v = 5 sqrt(1 + s). Here v is in ms^-1 and s in metres. Select the correct alternative.

Power of the only force acting on a particle of mass m=1 kg moving in straight line depends on its velocity as P=v^(2) where v is in m/s and P is in watt. If initial velocity of the particle is 1m/s, then the displacement of the particle in ln2 second will be :

Power of the only force acting on a particle of mass m=1 kg moving in straight line depends on its velocity as P=v^(2) where v is in m/s and P is in watt. If initial velocity of the particle is 1m/s, then the displacement of the particle in ln2 second will be :

For a particle moving along a straight line, its velocity 'v' and displacement 's' are related as v^(2) = cs , here c is a constant. If the displacement of the particle at t = 0 is zero, its velocity after 2 sec is:

A particle in moving in a straight line such that its velocity is given by v=12t-3t^(2) , where v is in m//s and t is in seconds. If at =0, the particle is at the origin, find the velocity at t=3 s .

A particle moves in a straight line such that its displacement is s^(2)=t^(2)+1 Find. (i) velocity

A particle starts from rest and moves along a straight line such that its acceleration a as a function of velocity v is given as a=(5)/(3v+2) where a is in m/s^(2) and v is in m/s .The distance travelled by the particle till it attains velocity of 10m/s is

The velocity of a particle moving in a straight line is decreasing at the rate of 3 m//s per metre of displacement at an instant when the velocity is 10 m//s. Determine the acceleration of the particle at this instant.