In moving from A to B along an electric field line, the work done by the electric field on an electron is `6.4 xx 10^-19 J`. If `phi_1 and phi_2` are equipotential surfaces, then the potential difference `V_C - V_A ` is.
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When an electron moves from A to B along and electric field line as shown in Fig. the electric field does 3.94xx10^(-19)J of work on it. What are the electric potential differences (V_(B) - V_(A)) , (V_(C) - V_(A)) , (V_(C) - V_(B)) ?

If a particle moves on an equipotential surface of an external field, work done by the electric field on the charge is

A and B are two points in an electric field . If the work done in carrying 4.0 C of electric charge from A to B is 16.0 J , the potential difference between A and B is

The figure shows some of the electric field lines corresponding to an electric field. If E is the intensity of electric field and V is the potential

15 joule of work has to be done against an existing electric field to take a charge of 0.01 C from A to B. Then the potential difference (V_(B) - V_(A)) is :-

The work done in carrying an electron from point A to a point B in an electric is 10 MJ. The potential difference (V_(B)-V_(A)) is then

12 j of work has to be done against an existion electric field to take a charge of 0.01 C from A to B. How much is th potential difference V_B - V_A?

12 j of work has to be done against an existion electric field to take a charge of 0.01 C from A to B. How much is th potential difference V_B - V_A?

When a point charge of 6 mu C is moved between two points in an electric field, the work done is 1.8 xx 10^(-5) J . The potential difference between the two points is :

The potential at a certain point in an electric field is 200 V. The work done in carrying an electron upto that point will be