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Na^(+) and CI^(-) both are removed by...

`Na^(+) and CI^(-)` both are removed by

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Permanent hardness is due to CI^(ɵ) and SO_4^(2-) of Mg^(2+) and Ca^(2+) and is removed by adding Na_2CO_3 . {:(CaSO_(4)+Na_(2)CO_(3)toCaCO_(3)+Na_(2)SO_(4)),(CaCl_(2)+Na_(2)CO_(3)toCaCO_(3)+2NaCl):} Which of the following statements is // are correct?

Permanent hardness is due to CI^(ɵ) and SO_4^(2-) of Mg^(2+) and Ca^(2+) and is removed by adding Na_2CO_3 . {:(CaSO_(4)+Na_(2)CO_(3)toCaCO_(3)+Na_(2)SO_(4)),(CaCl_(2)+Na_(2)CO_(3)toCaCO_(3)+2NaCl):} Which of the following statements is // are correct?

Permanent hardness is due to CI^(ɵ) and SO_4^(2-) of Mg^(2+) and Ca^(2+) and is removed by adding Na_2CO_3 . {:(CaSO_(4)+Na_(2)CO_(3)toCaCO_(3)+Na_(2)SO_(4)),(CaCl_(2)+Na_(2)CO_(3)toCaCO_(3)+2NaCl):} Which of the following statements is // are correct?

Both temporary and permanent hardness in water are removed by :

The distance between Na^(+) and CI^(-) ion ion NaCI is 281 pm. What is the edge length of the cube

5.85 g NaCI is dissolved in 1 litre water. The total number of ions of Na^(+) and CI^(-) in 1 mL of this solution will be :

5.85 g NaCI is dissolved in 1 litre water. The total number of ions of Na^(+) and CI^(-) in 1 mL of this solution will be :

In the distance between Na^(+) and CI^(-) ions in sodium chliride crystal is X pm , the length of the edge of the unit cell is

In the distance between Na^(+) and CI^(-) ions in sodium chloride crystal is y pm , the length of the edge of the unit cell is