A car is moving with velocity V. If stop after applying break at a distance of 20 m. If velocity of car is doubled, then how much distance it will cover (travel) after applying break :

A car moving with a velocity of 20ms^(-1) is stopped in a distance of 40m. If the same car is travelling at double the velocity, the distance travelled by it for same retardation is

A car moving with a velocity of 20 ms^(-1) is stopped in a distance of 40 m. If the same car is travelling at double the velocity, the distance travelled by it for same retardation is?

A car moving with a velocity of 20 ms^(-1) is stopped in a distance of 40 m. If the same car is travelling at double the velocity, the distance travelled by it for same retardation is

A car moving with a velocity v is stopped within a distance x by applying a retarding force F. If the speed of the car is doubled, then the force required to stop the car with the same distance is

A car is moving at a velocity 72 km/h. Brakes were applied. After moving a distance 200 m the car attains velocity 36 km/h.What distance will the train move before coming to rest.

A car is moving with a velocity of 72km/h. By applying brakes a negative acceleration of 0.4m/s2 is produced. the distance covered by the car before it stops?

A car moving with a speed v is stopped by applying brakes with in a distance s and time t. If it would have been travelling with Kv then by applying same breaking force it can be stopped with in

A car is moving with a velocity V. The car driver sees a truck at rest at a distance s. To avoid collision which is better, to apply brake or to turn sharply ?

A moving train is stopped by applying brakes. It stops after travelling 80 m . If the speed of the train is doubled and retardation remain the same, it will cover a distance-