37,x^(8)-1

If f(x)={{:(3x^(2)+12x-1",",-1lexle2),(37-x",",2ltxle3):} , Then

If f(x)=3x^(2)+12x-1,-1lexle2,=37-x,2ltxle3 , then :

The expression ((1+tan37^(@))(1+tan8^(@))(1+tan15^(@))(1+tan30^(@)))/((1+tan2^(@))(1+tan43^(@))) reduces to

Find: 37.8-:1.4

The value of ((1+tan8^(@))(1+tan37^(@)))/((1+tan22^(@))(1+tan23^(@)))

If n(A) = 37, n(B) = x, n(A cup B) = 52, n(A cap B) = 8 , then x =

Let A=[{:(3,7),(2,5):}] and B=[{:(6,8),(7,9):}] Verify that (AB)^(-1)=B^(-1)A^(-1)