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The bisector of angleB of an isosceles t...

The bisector of `angleB` of an isosceles triangle ABC with `AB=AC` meets the circumcircle of `triangleABC` at P as shown in the figure. If AP and BC produced meet at Q prove that `CQ=CA`.

Text Solution

Verified by Experts

From diagram
`/_Q=x`
`/_CAQ` is isoceles
CA=CQ.
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