int[sin x+cos x],[4+16sin2x]

int(sin x+cos x)/(9+16sin2x)

Evaluate :int(sin x+cos x)/(9+16sin2x)dx

Evaluate: int(sin x+cos x)/(9+16sin2x)dx

int(4sin x+4cos x)/(9+16sin2x)dx

Evaluate: int(sin x cos x)/(3sin^(2)x-4cos^(2)x)dx

Evaluate the following integrals int_(0)^(pi/4) (sin x + cos x)/(9+ 16 sin 2x) dx

The value of int_( sin )x cos x cos2x cos4x cos8x cos16x)dx is int(sin x cos x cos2x cos4x cos8x cos16x)dx is equal to

int_(0)^(pi//4)(sin x + cos x)/(9+16 sin 2 x )