[sec(90^(@)-theta)cosec theta-tan(90^(@)-theta)cot theta+cos^(2)25^(@)],[+cos^(2)65^(@)],[3tan27^(@)tan63^(@)]

Without using trigonometric tables,find the value of the following expression: (sec(90-theta)*cos ec theta tan(90-theta)cot theta+cos^(2)25+cos^(2)65)/(3tan27^(@)*tan63^(@))

Without using trigonometric table, the value of cotthetatan(90^(@)-theta)-sec(90^(@)-theta)"cosec"theta+sin^(2)65^(@)+sin^(2)25^(@)+sqrt3tan5^(@)tan85^(@) .

Prove that :(sin theta cos(90^(0)-theta)cos theta)/(sin(90^(0)-theta))+(cos theta sin(90^(0)-theta)sin theta)/(cos(90^(@)-theta))=1csc^(2)(90^(@)-theta)-tan^(2)theta=cos^(2)(90^(@)-theta)+cos^(2)theta

(tan(90^@-theta) cot theta)/(cosec^2 theta)-cos^2 theta=0

tan^(2)(90^(@) - theta) - cosec^(2) theta =

tan^(2)(90^(@) - theta) - cosec^(2) theta =

(sec theta+csc theta)^(2)-(tan theta+cot theta)^(2)=

Prove that : (i) sinthetacos(90^(@)-theta)+sin(90^(@)-theta)costheta=1 (ii) sectheta" cosec"(90^(@)-theta)-tanthetacot(90^(@)-theta)=1 (iii) (sintheta*sec(90^(@)-theta)cot(90^(@)-theta))/("cosec"(90^(@)-theta)*costheta*tantheta)-(tan(90^(@)-theta))/(cottheta)=0 (iv) (1+sin(90^(@)-theta))/(cos(90^(@)-0))+(cos(90^(@)-theta))/(1+sin(90^(@)-0))=2"cosec"theta

Prove that : (i) sinthetacos(90^(@)-theta)+sin(90^(@)-theta)costheta=1 (ii) sectheta" cosec"(90^(@)-theta)-tanthetacot(90^(@)-theta)=1 (iii) (sintheta*sec(90^(@)-theta)cot(90^(@)-theta))/("cosec"(90^(@)-theta)*costheta*tantheta)-(tan(90^(@)-theta))/(cottheta)=0 (iv) (1+sin(90^(@)-theta))/(cos(90^(@)-0))+(cos(90^(@)-theta))/(1+sin(90^(@)-0))=2"cosec"theta