The potential energy of particle of mass m varies as
`U(x)={(E_(0)"for"0lexle1),(0" for " gt 1):}`
The de Broglie wavelength of the particle in the range `0lexle1 " is " lamda_(1)` and that in the range `xgt1" is "lamda_(2)`.
If the total of the particle is `2E_(0)," find "lamda_(1)//lamda_(2)`.

The potential energy of a particle of mass m is given by U(x){{:(E_(0),,,0lexlt1),(0,,,xgt1):} lambda_(1) and lambda_(2) are the de-Broglie wavelength of the particle, when 0le x le1 and x gt 1 respectively. If the total energy of particle is 2E_(0) , then the ratio (lambda_(1))/(lambda_(2)) will be

The potential energy of a particle varies as . U(x) = E_0 for 0 le x le 1 = 0 for x gt 1 for 0 le x le 1 de- Broglie wavelength is lambda_1 and for xgt1 the de-Broglie wavelength is lambda_2 . Total energy of the particle is 2E_0 . find (lambda_1)/(lambda_2).

The potential energy of a partical varies as . U(x) = E_0 for 0 le x le 1 = 0 for x gt 1 for 0 le x le 1 de- Broglie wavelength is lambda_1 and for xgt1 the de-Broglie wavelength is lambda_2 . Total energy of the partical is 2E_0 . find (lambda_1)/(lambda_2).

The potential energy of a partical varies as . U(x) = E_0 for 0 le x le 1 = 0 for x gt 1 For 0 le x le 1 , de- Broglie wavelength is lambda_1 and for xgt the de-Broglie wavelength is lambda_2 . Total energy of the partical is 2E_0. find (lambda_1)/(lambda_2).

The potential energy of a partical varies as . U(x) = E_0 for 0 le x le 1 = 0 for x gt 1 For 0 le x le 1 , de- Broglie wavelength is lambda_1 and for xgt the de-Broglie wavelength is lambda_2 . Total energy of the partical is 2E_0. find (lambda_1)/(lambda_2).

The potential energy of a particle of mass m is given by V(x) = lambda_(1) and lambda_(2) are the de - Brogle wavelength of the particle, when = lex le 1 and xgt 1 repectively ,if the total energy of particle is 2 E_(0) find lambda_(1) // lambda_(2)

The de Broglie wavelength of a moving particle of mass m is lamda . For a few particles of different masses

A particle of mass M at rest decays into two masses m_(1) and m_2 with non zero velocities. The ratio of de-Broglie wavelengths of the particles (lamda_(1))/(lamda_(2)) is