[" 23.Two identical positive charges are placed at "],[x=-" a and "x=" a.The correct variation of "],[" potential "V" along the "x" -axis is given by: "]

Two identical positive charges are kept as shown in Fig < 0 x a The variation of electric field intensity E along x-axis is given by (The electric field intensity towards positive x-axis is taken as positive)

Two point charge +-q are placed on the axis at x= -a and x= +a , as shown in fig. (i) Plot the variation of E along the x-axis. (ii) Plot the variation of E along the y-axis.

Two point charge +-q are placed on the axis at x= -a and x= +-a , as shown in fig. (i) Plot the variation of E along the x-axis. (ii) Plot the variation of E along the y-axis.

Three charges are placed along x- axis at x = -a , x=0 and x=a as shown . Calculate the potential energy of the system.

Three charges are placed along x-axis at x = - a x = 0 and x = a as shown in the figure. The potential energy of the system is

Two identical positive charges Q each are placed on the x axis at point (-a,0) and (a,0) A point charge of magnitude q is placed at the origin. For small displacement along x axis, the charge q executes simple harmonic motion if it is poitive and its time period is T_(1) . if the charge q is negative, it perform oscillations when displaced along y axis. in this case the time period of small oscillations is T_(2). find (T_(1))/(T_(2))

The charges - q, Q, -q are placed along x-axis at x = 0, x = a and x = 2a. If the potential energy of the system is zero, then Q:q is

Two equal point charges are placed on x=-a and x=+a on the x=axis. Another point charge Q is placed on the origin. IF this charge is displaced a small distance x along x-axis, then the change of potential energy approximately will be proportional to