theta=sin^(-1)[sin(-600^(@))]

Simplify the following: Evaluate sin^(-1)[sin(-600^(@))]

The value of sin^(-1){sin(-600^(@))} is

The value of sin^(-1){sin(-600^(@))} is

If sin^(-1) theta = sin^(-1)(sin5) then theta is:

Prove that sin theta sin(60^(@)-theta) sin(60^(@)+theta)=1/4 sin3theta .

Prove that sin theta sin(60^(@)-theta) sin(60^(@)+theta)=1/4 sin3theta .

Prove that sin^(2)theta+sin^(2)2 theta+sin^(2)3 theta+....+sin^(2)n theta=(n)/(2)-(sin n theta cos(n+1)theta)/(2sin theta)

If: cos^(-1) (sin theta) = sin^(-1) (cos theta) , then: theta =

Prove that sin theta+sin3 theta+sin5 theta+....+sin(2n-1)theta=(sin^(2)n theta)/(sin theta)