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y^(2)+7y+12=0...

y^(2)+7y+12=0

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Quantity I: 'x':x^(2)+x-12=0 Quantity II. 'y' :y^(2)+7y+10=0

(i) x^(2)-7x+12=0 (ii) y^(2)+y-12=0

Find the factors of y^(2)-7y+12

Factorise the y ^(2) + 7y + 12

Find the factors of y^2 –7y +12 .

The four straight lines given by the equations 2x^(2)+7xy12y^(2)=0 and 12x^(2)+7xy-12y^(2)-x+7y-1=0 lie along the sides of a

I. 10x^(2) - 7x + 1= 0" " II. 35y^(2) - 12y + 1 = 0

I. x^(2) -7x + 12 = 0" "II. 3y^(2) - 11y + 10 = 0