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If bar(DA) =bar(a); bar(AB)=bar(b) and b...

If `bar(DA) =bar(a); bar(AB)=bar(b)` and `bar(CB)=kbar(a)` where `k>0` and `X,Y` are the midpoint of `DB` and `AC` respectively such that `|bar(a)|=17` and `|bar(XY)|=4`, then k=

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