[" 5.uf "(a)/(b+c),(b)/(c+a),(c)/(a+b)" A.P."pi" to at "a+b+c!=0," so fिIs at for "],[qquad (1)/(b+c),(1)/(c+a),(1)/(a+b)" A.P."Z" bil "]

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If (1)/(b+c),(1)/(c+a),(1)/(a+b) are in A.P., then

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