" (ii) "2x^(2)+3y^(2)-5=0" at "(1,1)

Find the equations of tangent and normal to the curves at the indicated points on it 2x^(2)+3y^(2)-5=0 at (1,1)

Find the equations of the normals to the following curves at the given points : 2x^(2)+3y^(2)-5=0 at (1, 1)

The equation of tangent to the curve 2x^(2)+3y^(2)-5=0 at (1,1) is

The equation of normal to the curve 2x^(2)+3y^(2)-5=0 at (1,1) is

Equation of the tangent to the curve 2x^(2)+3y^(2)-5=0 at (1, 1) is

Find the equations of tangent and normal to the following curves at the individual points on them: 2x^2 + 3 y^2-5 = 0 at (1, 1)

If 2x^(2)+3y+5y^(2)+x+9=0," then "((dy)/(dx))at(-1,-1) is

If x ^(2) - 2x ^(2) y ^(2) + 5x + y-5 =0 and y (1) then y '' (1)=

Solution of D.E (dy)/(dx)=(2x+5y)/(2y-5x+3) is,if (y(0)=0) (1) x^(2)-y^(2)+5xy-3y=0 (2) x^(2)+y^(2)+5xy-3y=0 (3) x^(2)-y^(2)+5xy+3y=0 (4) x^(2)-y^(2)-5xy-3y=0