0.25(4f-3)=0.05(10f-9)

Simplify and solve the linear equations.025(4f-3)=005(10f-9)

Simplify and solve the following linear equations : 0.25 (4y-3)=0.5 y-9

((0.05)/(0.25)+(0.25)/(0.05))^(3)=?( a) 139.4(b)140(c)140.6(d)143.9

Simplify: [(2 10/27))^(-2/3) ÷ (11 1/9))^(-0.5)] +[(6.25)^(0.5) ÷ (-4)^(-1)]

Let f(x)={{:(,3^x,at,-1lt x lt0),(,4,at,0 le x lt 1),(,3x-1, at,1 le x le 3):} Find f(2), f(0), f(0.5), f(-0.5), f(3).

In the Mean value theorem f(b)-f(a)=(b-a)f'(c), if a=4, b=9 and f(x)= sqrtx , then the value of c is (A)8.00 (B)5.25 (C)4.00 (D)6.25

If f(x) is a polynomial function satusfying the condition f(x)*f((1)/(x))=f(x)+f((1)/(x))and f(2)=9 then (1)2(f(4)=3f(6)(2)14f(1)=f(3)(3)9f(3)=f(5)(4)f(10)=f(11)