Calculate the daily loss of energy by the earth, if the temperature gradient in the earth's crust is `32^(@)C` per km and mean conductivity of the rock is `0.008` of CGS unit. (Given radius of earth `=6400km`)

Calculate the capacitance of the earth of radius 6400 km .

Heat received by the Earth due to solar radiations is 1.35 KWm^(-2) . It is also known that the temperature of the Earth’s crust increases 1^(@)C for every 30 m of depth. The average thermal conductivity of the Earth’s crust is K = 0.75 J (msK)^(-1) and radius of the Earth is R = 6400 km . (i) Calculate rate of heat loss by the Earth’s core due to conduction. (ii) Assuming that the Earth is a perfect block body estimate the temperature of its surface.

Find out the capacitance of the earth ? (Radius of the earth = 6400 km)

Find out the capacitance of the earth ? (Radius of the earth = 6400 km)

State the order of magnitude of radius of the earth. Given R = 6400 km

Find the weight of the atmosphere around the earth (take the radius of earth as 6400km)

Find the weight of the atmosphere around the earth (take the radius of earth as 6400km.)

Find the weight of the atmosphere around the earth (take the radius of earth as 6400km.)

Calculate the electrical capacitance of earth. The radius of earth is 6400 km.

The radius of the earth is 6400 km, the order of magnitude is