A mixtures of methane and ethylene in the volume ration x:y has total volume of 30mL. On complete combustion it gave 40mL of `CO_(2)`. IF the ratio of original mixture is y:x instead of x:y. What volume of `CO_(2)` would have been produced a combustion?

A mixture of methane and ethylene in the volume ratio x : y has a total volume of 30 ml . On complete combustion it gave 40 ml of CO_(2) . If the ratio had been y :x , instead of x : y , what volume of CO_(2) could have been obtained ?

A mixture of CH_(4) and C_(2)H_(4) in the volume ratio X : Y has total volume 30 ml. On complete combustion it gave 40 ml CO_(2) . If the ratio in the original mixture has been Y : X instead of X : Y, the volume of CO_(2) would have been produced on combustion is

10ml of an alkane on complete combustion gave 40ml of CO_(2) under the same conditions. The formula of the alkane is

6 litre of mixture of methane and propane on complete combustion gives 7 litre of CO_(2) . Find out the composition of the mixture ?

6 litre of mixture of methane and propane on complete combustion gives 7 litre of CO_(2) . Find out the composition of the mixture ?

40 ml of gaseous mixture of CO and ethyne is mixed with 100 ml of O_2 and burnt. The volume of gases after combustion is 105 ml. The composition of the original mixture is

40 ml of gaseous mixture of CO and ethyne is mixed with 100 ml of O_2 and burnt. The volume of gases after combustion is 105 ml. The composition of the original mixture is