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[" 56) "cot sin theta+cos theta=x," xì "...

[" 56) "cot sin theta+cos theta=x," xì "],[sin^(6)theta+cos^(6)theta=(1)/(4)[4-3(x^(2)-1)^(2)]" 2) "],[" HI "2" शsu "₫1" े."]

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If sin theta+cos theta=x, Prove that :sin^(6)theta+cos^(6)theta=(4-3(x^(2)-1)^(2))/(4)

If sin theta+cos theta=x then prove that sin^(6)theta+cos^(6)theta=(4-3*(x^(2)-1)^(2))/(4)

sin^(6)theta+cos^(6)theta+3sin^(2)theta cos^(2)theta=1

Prove that sin^(6)theta+cos^(6)theta=1-3sin^(2)theta cos^(2)theta

Prove that sin^(6)theta+cos^(6)theta=1-(3)/(4)sin^(2)2 theta

cos^(3)2 theta+3cos2 theta=4(cos^(6)theta-sin^(6)theta)

Prove that sin^(6)theta+cos^(6)theta=1-3sin^(2)theta.cos^(2)theta.

Prove that: sin^(6) theta + cos^(6) theta =1 - 3 sin^(2) theta cos^(2) theta

2(sin^(6) theta + cos^(6)theta) - 3(sin^(4)theta + cos^(4)theta)+ 1 = 0