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" Liquids "A" and "B" form an ideal solu...

" Liquids "A" and "B" form an ideal solution "

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Two liquids A and B form an ideal solution. The ratio of vapour pressures of pure liquids A and B are 3: 5. If the mole fraction of A in the liquid solution at equilibrium with vapours is 0.4, then the mole-fraction of B in the liquid is

The vapour pressures of two pure liquids A and B that form an ideal solution are 300 and 800 torr, respectively, at tempertature T . Calculate The composition of the first drop of the condensate. A mixture of the vapours of A and B for which the mole fraction A is 0.25 is slowly compressed at temperature T.

Liquid A and B form an ideal solution. The boiling point of solution is 72^(@) C, when the external pressure is 0.6 bar. If then solution contains 200 moles of liquid A, then moles of liquid B is : [Given : P_(A)^(@)=0.4 "bar" "and" P_(B)^(@)=1.0 "bar" "at" 72^(@)C]

Two liquid A and B form an ideal solution at temperature T. When the total vapout pressure above the solution is 400 torr , the mole fraction of A in the vapour phase is 0.40 and in the liquid phase 0.75. What are the vapour pressure of pure A and pure B at temperature T?

Liquid A and B form an ideal solution. At 25^(@)C . 5 moles of vapours of liquid 'A' and 10 moles of vapour of liquid B are taken in a cylinder piston arrangement and a pressure of 0.6 bar is maintained. At 25^(@)C , P_(A)^(@)=0.5 bar , P_(B)^(@) =1.0 bar. The only correct statement about the system is :