[" if "A=[[2,-2],[-2,2]]" is and "A^(2)=PA],[" then find "P]

If the matrix A=[{:(2,-2),(-2,2):}] and A^(2)=PA , then write the value of P.

If matrix A=[2-2-22] and A^(2)=pA then write the value of p.

A(2,3) , B (1,5), C(-1,2) are the three points . If P is a point such that PA^(2)+PB^(2)=2PC^2 , then find locus of P.

A(2,3) , B (1,5), C(-1,2) are the three points . If P is a point such that PA^(2)+PB^(2)=2PC^2 , then find locus of P.

" If A is a "2times2" matrix with real entries so that "A^(2)=3A-2I," and "p,q" belongs to integers such that "A^(8)=pA+qI," then "p+q" is "

A(2,3),B(1,5),C(-1,2) are three points and PA^(2)+PB^(2)=2PC^(2) then locus of P is

The coordinates of the point A and B are (a,0) and (-a,0), respectively.If a point P moves so that PA^(2)-PB^(2)=2k^(2), when k is constant,then find the equation to the locus of the point P.

The equations of two circles are x^(2)+y^(2)+2 lambda x+5=0 and x^(2)+y^(2)+2 lambda y+5=0.P is any point on the line x-y=0. If PA and PB are the lengths of the tangent from Ptothe circles and PA=3 then find PB.

If A(3,4,1) and B(-1,2,3) are two points, then find the locus of a moving point P such that PA^(2)+PB^(2)=2k^(2) .

If A(3,4,1) and B(-1,2,3) are two points, then find the locus of a moving point P such that PA^(2)+PB^(2)=2k^(2) .