The distance of the point `(1,-2,3)` from the plane `x-y+z=5` measured parallel to the line `x/2=y/3=z/-6`, is

Find the distance of the point (1,-2,3) from the plane x-y+z=5 measured parallel to the line x/2=y/3=z/-6 .

Find the distance of the point (1,-2,3) from the plane x-y+z=5, measured parallel to the line x/2=y/3=z/(-6)

The distance of the point (1,-2,3) from the plane x-y+z-5=0 , measured parallel to the line x/2=y/3=(z-1)/-6 is equal to

The distance of the point (1,-2,3) from the plane x-y+z-5=0 , measured parallel to the line x/2=y/3=(z-1)/-6 is equal to

Find the distance of the point (1,-2,3) from the plane x-y+z=5 measured parallel to the line (x)/(2)=(y)/(3)=(z)/(-6) .

Find the distance of the point (1, - 2, 3) from the plane x - y + z = 5 , measured parallel to the line x/2=y/2=z/-6

Find the distance of the point (1,-2,3) from the plane x-y+z=5 measured parallel to the line (x-1)/2=(y-3)/3=(z+2)/-6 .

The distance of point (1,-2,-3) from plane x-y+z=5 measured parallel to the line x/2=y/3=z/(-6) is

Find the distance of the point (1,-2,3) from the plane x - y + z = 5, measured parallel to the line : (x)/(2) = (y)/(3) = (z)/(-6) .