[x+y=2a],[47*(bx)/(a)+(ay)/(b)=a^(2)+b^(2)],[x+y=2ab]

(bx)/(a)-(ay)/(b)+a+b=0 and bx-ay+2ab

(b/a)x+(a/b)y=a^2b^2; x+y=2ab

Solve the following system of equations in x and yax+by=1bx+ay=((a+b)^(2))/(a^(2)+b^(2))-1 or,bx+ay=(2ab)/(a^(2)+b^(2))

Find the value of y by eliminating x : (x+a)/(2a+b)=(y+2b)/(a+b), bx+ay=a^(2)+b^(2)

If (x+1)/(x-1)=(a)/(b) and (1-y)/(1+y)=(b)/(a), then the value of (x-y)/(1+xy) is (2ab)/(a^(2)-b^(2)) (b) (a^(2)-b^(2))/(2ab) (c) (a^(2)+b^(2))/(2ab) (d) (a^(2)-b^(2)backslash)/(ab)

(a)/(x)-(b)/(y)=0,(ab^(2))/(x)+(a^(2)b)/(y)=a^(2)+b^(2)

Solve (by any method) : (x+a)/(2a+b)=(y+2b)/(a+b) bx+ay=a^(2)+b^(2)

If (x)/(a)+(y)/(b)=1 intersects 5x^(2)+5y^(2)+5bx+5ay-9ab=0 at P and Q,/_POQ=(pi)/(2) then the relation between a and b is (A) a=b(B)a=2b or b=2a(C)a=3b or b=3a(D)a+b=5