Reducing character decreases from `SO_(2) " to " TeO_(2)`. Explain.

Account for the following : Reducing character decreases from SO_(2) to TeO_(2) .

(a)Account for the following (i) Reducing character decreases from SO_(2) to TeO_(2). (ii) HClO_(3) is a stronger acid than HClO. (iii) Xenon forms compounds with fluorine and oxygen only. (b) Complete the following equations : (i) 4NaCl+MnO_(2)+4H_(2)SO_(4)to (ii) 6XeF_(4)+12H_(2)Oto

Account for the following (i) Reducing character decreases from SO_(2) to TeO_(2). (ii) HClO_(3) is a stronger acid than HClO. (iii) Xenon forms compounds with fluorine and ozygen only. (b) Complete the following equations : (i) 4NaCl+MnO_(2)+4H_(2)SO_(4)to (ii) 6XeF_(4)+12H_(2)Oto

Account for the following: Reducing character decreases from NH_3 to BiH_3 .

Reducing property of dioxides decreases from SO_2 to TeO_2 . Why ?

Given below are two statements labelled as Assertion (A) and Reason (R) Assertion(A): SO_2 is reducing while TeO_2 is an oxidising agent. Reason(R):Reducing property of dioxide decreases from SO_2 to TeO_2 . Select the most appropriate answer from the options given below:

The statements about oxides of chalcogens i) The solubility of dioxides decreases from SO _(2) to Po O _(2) ii) TeO _(2) is highly acidic in nature (iii) Trioxides are more acidic than dioxides The correct combination is

Statement 1: Metallic character decreases from left to right. Statement 2: Ionization enthalpy increase and electronegativity decreases.