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Number of ways in which 9 different toys...

Number of ways in which 9 different toys be distributed among 4 children belonging to different age group in such a way that distribution among the 3 elder children is even and the youngest one is to receive one toy more is:

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Number of ways=` 2C_2*(4C_2)*(6C_2)*(9C_2)` =`1*((4!)/(2!*2!))*((6!)/(4!*4!))*((9!)/(7!*2!))` =` ((9!)/((2!)^3*(3!)))`
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