The electronic configuration of a dipositive ion `M^(2+)` is 2, 8, 14 and its mass number is 56. The number of netrons present is

The electronic configuration of a dipositive ion M2+ is 2,8,14 and its mass number is 56. What is the number of neutrons present?

The electronic configuration of a dipositive ion M^(2+) is 2, 8, 14 and its atomic mass is 56. what is the number of neutrons in its nucleus ?

The electronic configuration of a dispositive ion M^2 is 2,8,14 and its atomic mass is 56.What is the number of electrons,protons and nuetorns?

The electronic configuration of a dispositive metal ion M^(2+) is 2, 8, 14 and its ionic weight is 56 amu. The number of neutrons in its nucleus would be

An element has electronic configuration 2, 8, 18, 1. If its mass number is 63, then how many neutrons will be present in the nucleus of the atom?

In the atom of an element 7 electrons are present in the M shell. : There are 18 neutrons in the nucleus of atom: a)Write down the electronic configuration of the given atom. b) What is its.mass number? c). How many electrons are present in it.