" If the mean of the observations "x_(1),x_(2)....,x_(n)" is "bar(x)," show that "sum_(i=1)^(n)(x_(1),bar(x))=0

If barx is the mean of n observations x_(1),x_(2),x_(3)……x_(n) , then the value of sum_(i=1)^(n)(x_(i)-barx) is (i) -1 (ii) 0 (iii) 1 (iv) n-1

If barx is the mean of n observations x_(1),x_(2),x_(3)……x_(n) , then the value of sum_(i=1)^(n)(x_(i)-barx) is (i) -1 (ii) 0 (iii) 1 (iv) n-1

If barx represents the mean of n observations x_(1), x_(2),………., x_(n) , then values of Sigma_(i=1)^(n) (x_(i)-barx)

If barx represents the mean of n observations x_(1), x_(2),………., x_(n) , then values of Sigma_(i=1)^(n) (x_(i)-barx)

The average of n numbers x_(1), x_(2), ……. X_(n) is bar(x) . Then the value of sum_(i=1)^(n) (x_(1) - bar(x)) is equal to

If the mean of a set of observations x_(1),x_(2), …,x_(n)" is " bar(X) , then the mean of the observations x_(i) +2i , i=1, 2, ..., n is

If the mean of a set of observations x_(1),x_(2), …,x_(n)" is " bar(X) , then the mean of the observations x_(i) +2i , i=1, 2, ..., n is

If the mean of a set of observations x_(1),x_(2), …,x_(n)" is " bar(X) , then the mean of the observations x_(i) +2i , i=1, 2, ..., n is

If the mean of n observations x_(1),x_(2),x_(3)...x_(n) is bar(x) then the sum of deviations of observations from mean is