Prove that if two bubbles of radii `r_(1)` and `r_(2)` coalesce isothermally in vacuum then the radius of new bubble will be `r=sqrt(r_(1)^(2)+r_(2)^(2))`

Two soap bubbles of radii 1 mm and 2 mm merge isothermally . Then radius of the new bubble formed would be

Two soap bubbles of radius R_1 and R_2 combine isothermally to form a new soap bubble. Find radius of new soap bubble

Two soap bubbles of radii r_1 and r_2 combine to form a bigger bubble under isothermal conditions. The radius of bigger bubble will be

Prove that if two bubbles of radii r_(1) and r_(2)(r_(1)ltr_(2)) come in contact with each other then the radius of curvature of the common surface r=(r_(1)r_(2))/(r_(2)-r_(1))

Prove that if two bubbles of radii r_(1) and r_(2)(r_(1)ltr_(2)) come in contact with each other then the radius of curvature of the common surface r=(r_(1)r_(2))/(r_(2)-r_(1))

Two soap bubbles of different radii r_(1)andr_(2) are in contact. Determine the radius of the interface.

When two soap bubbles of radii r_1 and r_2 ( r_2>r_1 )coalese, the radius of curvature of common surface is