underset(("Coloured solution"))(P)+BaCl(...

`underset(("Coloured solution"))(P)+BaCl_(2) to underset(("White"))(Qdarr)+underset(("Coloured solution"))(R)` ltBrgt Then salt 'P' in above reaction is:

`Na_(2)CrO_(4)`

`ZnSO_(4)`

`CuSO_(4)`

`AgNO_(3)`

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The correct Answer is:

`underset("blue solution")(CuSO_(4)) +BaCl_(2) to underset("white ppt")(BaSO_(4)darr)+underset("blue solution")(CuCl_(2))`

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