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Iron forms iron halides salts by reactin...

Iron forms iron halides salts by reacting the metal directly with halogen. `FeI_(3)` does not exist. `FeF_(3)` is white soled inspite of five unpaired electrons with `d^(5)` configuration . `FeCl_(3)` is soluble in water and is used as a mordant in dyeing industry.
Q.`FeI_(3)` does not exist because:

A

of large size

B

`Fe^(3+)` oxidise `I^(-)` to `I_(2)`

C

of low lattice energy

D

iodine is not highly electronegative enough to oxidise Fe to `Fe^(3+)`

Text Solution

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The correct Answer is:
B
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Iron forms iron halides salts by reacting the metal directly with halogen. FeI_(3) does not exist. FeF_(3) is white soled inspite of five unpaired electrons with d^(5) configuration . FeCl_(3) is soluble in water and is used as a mordant in dyeing industry. Q. FeCl_(3) solution added to K_(4)[Fe(CN)_(6)] gives A while with KSCN gives B. A and B respectively are:

Iron forms iron halides salts by reacting the metal directly with halogen. FeI_(3) does not exist. FeF_(3) is white soled inspite of five unpaired electrons with d^(5) configuration . FeCl_(3) is soluble in water and is used as a mordant in dyeing industry. Q.Anhydrous FeCl_(3) can be prepared by reaction of:

Read the passage given below and answer the following questions: Within the 3d series, manganese exhibits oxidation states in aqueous solution from +2 to +7, ranging from Mn^(2+)(aq) to MnO_(4)^(-) (aq). Likewise, iron forms both Fe^(2+)(aq) and Fe^(3+)(aq) as well as the FeO_(4)^(2-) ion. Cr and Mn form oxyions CrO_(4)^(2-) , MnO_(4)^(-) , owing to their willingness to form multiple bonds . The pattern with the early transition metals-in the 3d series up to Mn, and for the 4d, 5d metals up to Ru and Os—is that the maximum oxidation state corresponds to the number of ‘‘outer shell’’ electrons. The highest oxidation states of the 3d metals may depend upon complex formation (e.g., the stabilization of Co^(3+) by ammonia) or upon the pH (thus MnO_(4)^(2-) (aq) is prone to disproportionation in acidic solution). Within the 3d series, there is considerable variation in relative stability of oxidation states, sometimes on moving from one metal to a neighbor, thus, for iron, Fe^(3+) is more stable than Fe^(2+) , especially in alkaline conditions, while the reverse is true for cobalt. The ability of transition metals to exhibit a wide range of oxidation states is marked with metals such as vanadium, where the standard potentials can be rather small, making a switch between states relatively easy. (Cotton, S. A. (2011). Lanthanides: Comparison to 3d metals. Encyclopedia of inorganic and Bioinorganic Chemistry.) In the following questions, a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices on the basis of the above passage. Assertion: The highest oxidation states of the 3d metals depends only on electronic configuration of the metal. Reason: The number of electrons in the (n-1)d and ns subshells determine the oxidation states exhibited by the metal.

An inorganic halide (A) reacts with water to form two acids (B) and (c). (A) also reacts with NaOH to form two salts (D) and ( E) which remain in solution. The solution gives white precipitate with both AgNO_3 and BaCl_2 solutions respectively. (A) is a useful organic reagent. Identify (A) to ( E) .

A metal X forms a water-soluble seat XNO_(3) When an aqueous solution of XNO_(3) is added to the common salt solution, then a white precipitate of compound Y is formed along with sodium nitrate solution. Metal X is said to be the best conductor of electricity and it does not evolve hydrogen when put in dilute hydrochloric acid. (a) What is metal X ? (b) What is salt XNO_(3) ? (c ) Name the compound Y. (d) Write the chemical equation of the reaction which takes place on reaction XNO_(3) solution and common salt solution giving the physical states of all the reactants and products. (e) What type of chemical reaction is illustrated by the above equation?

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