[" 8.Tुणनखंड Try "],[" (i) "a^(3)+b^(3)-c^(3)+3abc]

(a^(3)+b^(3)-c^(3)+3abc)/(a+b-c)=

Factorise : a^(3)+b^(3)+c^(3)-3abc

Factorise (i) a^(3)+8b^(3)+64c^(3)-24abc

Factorise a^3+b^3+c^3-3abc

If a= 1.21, b= 2.23 & c= -3.44 find a^(3) + b^(3) +c^(3) + 3abc = ?

If a + b + c = 0 , show that a^(3) + b^(3) + c^(3) = 3abc The following are the steps involved in showing the above result. Arrange them in sequential order (A) a^(3) + b^(3) + 3ab (-c) = -c^(3) (B) (a + b)^(3) = (-c)^(3) (C) a + b + c = 0 rArr a + b = -c (D) a^(3) + b^(3) + 3ab (a +b) = -c^(3) (E) a^(3) + b^(3) + c^(2) = 3abc