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(dy)/(dx)" निकालें यदि "y=tan (x+y)...

`(dy)/(dx)" निकालें यदि "y=tan (x+y)`

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Solve: x (dy)/(dx)- y-x tan . (y/x) . = 0

(dy)/(dx) = y tan x, y = 1 when x = 0

(dy)/(dx) = y tan x, y = 1 when x = 0

(dy)/(dx) = y tan x, y = 1 when x = 0

(dy)/(dx) = y tan x, y = 1 when x = 0

(x (dy) / (dx) -y) tan ^ (- 1) ((y) / (x)) = x

(dy)/(dx)=y tan x , y=1 when x=0

(dy)/(dx)+y tan x=sec x