" lution of "2y sin x(dy)/(dx)=2sin x cos x-y^(2)cos x,x=(pi)/(2),y=1" is given by "

Solution of 2y sin x(dy)/(dx)=sin2x-y^(2)cos x,x=(pi)/(2),y=1 is given by

Solution of the differential equation 2y sin x(dy)/(dx)=2sin x cos x-y^(2)cos x satisfying y((pi)/(2))=1 is given by

Solution of the differential equation 2y sin x (dy)/(dx)=2 sin x cos x -y^(2) cos x satisfying y((pi)/(2))=1 is given by :

Solution of the differential equation 2 y sin x (dy)/(dx) = 2 sin x cos - y^(2) cos x satisfying y(pi//2) = 1 is given by

2y sin x backslash(dy)/(dx)=2sin x cos x-y^(2)cos x;y((pi)/(2))=1 then solution of the equation is

(dy) / (dx) = (sin x-sin y) (cos x) / (cos y)

y(dy)/(dx)sin x=cos x(sin x-(y^(2))/(2)); where at x=(pi)/(2)

(dy) / (dx) -y cos x = 2x sin x

Solution of differential equation sin y*(dy)/(dx)=(1)/(x)cos y=x^(4)cos^(2)y is