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If ^n+1C(r+1)dot^n Crdot^(n-1)C(r-1)=11 ...

If `^n+1C_(r+1)dot^n C_rdot^(n-1)C_(r-1)=11 :6:3,` then `n r=` `20` b. `30` c. `40` d. `50`

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