A particle is travelling in a straight line, it has a initial velocity of `10ms^(-1)`. When it is subjected to an acceleration of `-2ms^(-2)` for 8 sec. find displacement and distance traversed in 8 sec.

A particle moves in a straight line with constant velocity of 5 ms^(-1) for 2 sec. it then moves with a constant acceleration of -2ms^(-2) for 8 sec. draw velocity-time graph for 10 sec of motion and find (a). Final velocity (b). Displacement (c). Total distance.

A particle starts moving in +ve x direction with initial velocity of 10 ms^(-1) with a uniform acceleration of magnitude 2 ms^(-2) but directed in -ve x direction. What is the distance traversed by the particle in 12 seconds:

A motorcycle moving with a speed of 5 ms^(-1) is subjected to an acceleration of 0.2 ms^(-2) for 10 second. Calculate (a) the speed (b) the distance travelled.

An object starting from rest undergoes an acceleration of 8ms ^(-2) for 10 second. Find (a) the speed (b) the distance travelled.

A particle is moving along straight line with initial velocity +7m//sec and uniform acceleration -2m//sec^(2) . The distance travlled by the particle in 4th second of its motion is:

A particle has an initial velocity (3hati+2hatj) ms^(-1) and an acceleration of (0.2hati+0.3hatj)ms^(-2) . Its speed after 10s is

A particle has an initial velocity (6hati+8hatj) ms^(-1) and an acceleration of (0.8hati+0.6hatj)ms^(-2) . Its speed after 10s is

A particle has an initial velocity (6hati+8hatj) ms^(-1) and an acceleration of (0.8hati+0.6hatj)ms^(-2) . Its speed after 10s is