A simple pendulum has a time period `T_(0)` at north pole. Find time period at equator. Accunt for earth's rotation only.

A simple pendulum has a time period T. If the support and the pendulum fall freely, the time period will be

A simple pendulum has a time period T. If the support and the pendulum fall freely, the time period will be

A simple pendulum has a time period T_(1) on the surface of earth of radius R. When taken to a height of R above the earth's surface, its time period is T_(2) , ratio (T_(2))/(T) is

A simple pendulum oscillates in air with time period T and amplitude A . As the time passes

A simple pendulum has a time period T_(1) when on the earth's surface and T_(2) when taken to a height R above the earth's surface, where R is the radius of the earth. The value of (T_(2))/(T_(1)) is

A simple pendulum has a time period T_(1) when on the earth's surface and T_(2) when taken to a height R above the earth's surface, where R is the radius of the earth. The value of (T_(2))/(T_(1)) is