0" sinze "

If cosx+cosy+cosz=sinx+siny+sinz=0" then "cos(x-y)=

If cosx+cosy+cosz=sinx+siny+sinz=0" then "cos(x-y)=

If cosx + cosy + cosz = 0 and sinx + siny + sinz =0 , then show that cos (x-y) + cos(y - z) + cos(z - x) = - 3/2.

If cosx + cosy + cosz = 0 "and" sinx + siny + sinz =0, "then show that" cos (x-y) + cos(y - z) + cos(z - x) = - 3/2.

If cosx+cosy+cosz=sinx+siny+sinz=0" then "cos(x-y)= (a) 0 (b) -1/2 (c) 2 (d) 1

If cos(y-z)+cos(z-x)+cos(x-y)=-3/2, prove that cos x + cos y + cos z = 0 = sin x + siny + sinz.

If cosx + cosy + cosz = 0 = sinx + siny + sinz ,then possible value of cos((x-y)/2) is (A) 4 3 1 2 (B) 4 3 2 1 (C) 3 4 2 1 (D) 3 4 1 2

The value of the expression sinx+ siny + sinz where x, y, z are real numbers satisfying x+y+z= 180^@ is

If sinx + siny + sinz + sinzw = - 4. then the value of sin^(400)x + sin^(300) y + sin^(200) z + sin^(100) w is

I : Value of i^i=e^(-pi/2) II : z=ilog(2+sqrt3) then sinz=2 which of above statement is true